Question:

If the ratio of the absolute temperature of the sink and source of a Carnot engine is changed from 2:3 to 3:4, the efficiency of the engine changes by:

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Carnot efficiency depends on the temperature difference between the hot and cold reservoirs. A smaller temperature difference reduces efficiency.
Updated On: Mar 13, 2025
  • 25% 25\%
  • 40% 40\%
  • 50% 50\%
  • 15% 15\%
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The Correct Option is A

Solution and Explanation

To determine how the efficiency of a Carnot engine changes when the ratio of the absolute temperatures of the sink and source changes, we follow these steps: Given: 
- Initial temperature ratio: TsinkTsource=23 \frac{T_{\text{sink}}}{T_{\text{source}}} = \frac{2}{3}  
- New temperature ratio: TsinkTsource=34 \frac{T_{\text{sink}}}{T_{\text{source}}} = \frac{3}{4}  

Step 1: Calculate the Initial Efficiency The efficiency η \eta of a Carnot engine is given by: η=1TsinkTsource \eta = 1 - \frac{T_{\text{sink}}}{T_{\text{source}}} For the initial ratio: η1=123=1333.33% \eta_1 = 1 - \frac{2}{3} = \frac{1}{3} \approx 33.33\%  

Step 2: Calculate the New Efficiency For the new ratio: η2=134=14=25% \eta_2 = 1 - \frac{3}{4} = \frac{1}{4} = 25\%  

Step 3: Determine the Change in Efficiency
The change in efficiency Δη \Delta \eta is: Δη=η2η1=25 \Delta \eta = \eta_2 - \eta_1 = 25% - 33.33% = -8.33\% However, we are interested in the absolute change relative to the initial efficiency: Percentage Change=Δηη1×100%=8.33%33.33%×100%25% \text{Percentage Change} = \left| \frac{\Delta \eta}{\eta_1} \right| \times 100\% = \left| \frac{-8.33\%}{33.33\%} \right| \times 100\% \approx 25\%  

Final Answer: 25% \boxed{25\%} This corresponds to option (1).

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