Question:

If the range and time period of projectile are related to $ R=5{{T}^{2}}, $ then the angle of projection will be

Updated On: Jun 21, 2022
  • $ \pi /2 $
  • $ \pi /3 $
  • $ \pi /4 $
  • $ \pi /6 $
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The Correct Option is C

Solution and Explanation

$ T=\frac{2u\sin \theta }{g} $ $ R=\frac{{{u}^{2}}\sin 2\theta }{g} $ According to question, $ R=5{{T}^{2}} $ $ \frac{{{u}^{2}}\sin 2\theta }{g}=5{{\left( \frac{2u\sin \theta }{g} \right)}^{2}} $ $ \frac{2{{u}^{2}}\sin \theta .\cos \theta }{g}=\frac{20{{u}^{2}}{{\sin }^{2}}\theta }{g} $ $ \cos \theta =\frac{10\sin \theta }{{{g}^{2}}} $ $ \tan \theta =1 $ or $ \theta =\frac{\pi }{4} $
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration