We are given that $$ P(\text{correct}) = \frac{x}{12} $$ and $$ P(\text{not correct}) = \frac{5}{8} $$
We know that the sum of the probabilities of all possible outcomes is 1.
In this case, the only possible outcomes are guessing the correct answer or not guessing the correct answer.
Thus, $$ P(\text{correct}) + P(\text{not correct}) = 1 $$ $$ \frac{x}{12} + \frac{5}{8} = 1 $$
To solve for $x$, we can first subtract $\frac{5}{8}$ from both sides: $$ \frac{x}{12} = 1 - \frac{5}{8} = \frac{8}{8} - \frac{5}{8} = \frac{3}{8} $$ Now, multiply both sides by 12 to isolate $x$: $$ x = 12 \cdot \frac{3}{8} = \frac{12 \cdot 3}{8} = \frac{36}{8} = \frac{9}{2} = 4.5 $$
Therefore, the value of $x$ is 4.5.
If the probability distribution is given by:
| X | 0 | 1 | 2 | 3 | 4 | 5 | 6 | 7 |
|---|---|---|---|---|---|---|---|---|
| P(x) | 0 | k | 2k | 2k | 3k | k² | 2k² | 7k² + k |
Then find: \( P(3 < x \leq 6) \)
If \(S=\{1,2,....,50\}\), two numbers \(\alpha\) and \(\beta\) are selected at random find the probability that product is divisible by 3 :