If the population of a town is p in the beginning of any year then it becomes 3+2p in the beginning of the next year. If the population in the beginning of 2019 is 1000, then the population in the beginning of 2034 will be
We can modify each option for 'n' years: (997)214 + 3 ≡ (p-3)2n-1 + 3 (1003)215 + 6 ≡ (p-3)2n + 6 (1003)215 - 3 ≡ (p-3)n - 3 (997)15 - 3 ≡ (p-3)n - 3 Given the condition that in one year, the population 'p' becomes '3+2p', we substitute 1n=1 into each option and check to obtain3+2p: (p-3)2n-1 + 3 ≡ 3 ≠ 3 + 2p (p-3)n - 3 ≡ (p-3) - 3 ≠ p - 6 Therefore, the correct answer is option 3.