For the pair of equations to have infinite solutions, the second equation must be a scalar multiple of the first equation.
\[
\frac{9x + 12y}{3x + 4y} = \frac{6}{k} \quad \text{(divide both equations by 3x + 4y)}
\]
Simplifying, we get:
\[
\frac{9}{3} = \frac{6}{k} \quad \Rightarrow \quad 3 = \frac{6}{k} \quad \Rightarrow \quad k = 2.
\]