- The number of half-lives ($n$) required to reduce $256~g$ to $1~g$ is found by:
\[
\left(\frac{1}{2}\right)^n = \frac{1}{256}
\]
Since $256 = 2^8$, it implies:
\[
n = 8
\]
- Each half-life is $12.5$ hours, so total time ($t$) is:
\[
t = n \times \text{half-life} = 8 \times 12.5 = 100~\text{hours}
\]
Thus, it takes 100 hours for the substance to reduce from 256 g to 1 g.