Question:
If the function f(x) defined by
\(f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+...+\frac{x^2}{2}+x+1,\)
then f'(0)=
If the function f(x) defined by
\(f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+...+\frac{x^2}{2}+x+1,\)
then f'(0)=
\(f(x)=\frac{x^{100}}{100}+\frac{x^{99}}{99}+...+\frac{x^2}{2}+x+1,\)
then f'(0)=
Updated On: Sep 15, 2024
- 100f'(0)
- 1
- 100
- None of these
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The Correct Option is B
Solution and Explanation
The correct option is (B) : 1.
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