Question:
The function f(z) defined by \(f(z)= \begin{cases} \frac{Re(z)}{z} & z\neq0\\ 0 & z=0 \end{cases}\)then which one of the following is true?
The function f(z) defined by \(f(z)= \begin{cases} \frac{Re(z)}{z} & z\neq0\\ 0 & z=0 \end{cases}\)then which one of the following is true?
Updated On: Mar 12, 2025
- \(\lim\limits_{z\rightarrow0}f(z)\)exists
- f(z) is continuous at z=0
- f(z) is differentiable everywhere
- f(z) is not continuous at z=0
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The Correct Option is D
Solution and Explanation
The correct answer is(D): f(z) is not continuous at z=0
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