Question:
If the coordinates of one end of a diameter of the circle x2+y2+4x–8y+5=0, is (2,1), the coordinates of the other end is
If the coordinates of one end of a diameter of the circle x2+y2+4x–8y+5=0, is (2,1), the coordinates of the other end is
Updated On: Apr 27, 2024
- (A) (–6, –7)
- (B) (6, 7)
- (C) (–6, 7)
- (D) (7, –6)
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The Correct Option is C
Solution and Explanation
Explanation:
Centre circle (-2,4)
Centre circle (-2,4)
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