Question

If the collector and base currents of a transistor in common emitter configuration are 5 mA and 50 \(\mu\)A, then the current amplification factor of the transistor is

• A. \( 100 \)
• B. \( 200 \)
• C. \( 50 \)
• D. \( 400 \)

Hint:

Remember: \( \beta = \frac{I_C}{I_B} \), and always convert units (mA, µA) correctly before calculation.

Answer 1

The Correct Option is A

In common emitter configuration: \[ \beta = \frac{I_C}{I_B} \] Given: \( I_C = 5\, \text{mA} = 5 \times 10^{-3} \, \text{A} \), and \( I_B = 50\, \mu\text{A} = 50 \times 10^{-6} \, \text{A} \) \[ \beta = \frac{5 \times 10^{-3}}{50 \times 10^{-6}} = \frac{5000}{50} = 100 \]