Step 1: Sampling theorem.
According to the Nyquist-Shannon sampling theorem, the minimum sampling frequency \(f_s\) should be at least twice the highest frequency component of the signal.
Step 2: Relation between frequency and period.
The frequency \(f\) is the reciprocal of the period \(T\): \[ f = \frac{1}{T} \] Given the period is greater than 10 s, the frequency corresponding to the maximum period (10 s) is: \[ f = \frac{1}{10} = 0.1 \, {Hz} \] Step 3: Minimum sampling frequency.
To satisfy the Nyquist criterion, the minimum sampling frequency should be: \[ f_s = 2 \times 0.1 = 0.2 \, {Hz} \] Thus, the minimum sampling frequency should be \(0.2\) Hz.
Consider a medium of uniform resistivity with a pair of source and sink electrodes separated by a distance \( L \), as shown in the figure. The fraction of the input current \( (I) \) that flows horizontally \( (I_x) \) across the median plane between depths \( z_1 = \frac{L}{2} \) and \( z_2 = \frac{L\sqrt{3}}{2} \), is given by \( \frac{I_x}{I} = \frac{L}{\pi} \int_{z_1}^{z_2} \frac{dz}{(L^2/4 + z^2)} \). The value of \( \frac{I_x}{I} \) is equal to 
Suppose a mountain at location A is in isostatic equilibrium with a column at location B, which is at sea-level, as shown in the figure. The height of the mountain is 4 km and the thickness of the crust at B is 1 km. Given that the densities of crust and mantle are 2700 kg/m\(^3\) and 3300 kg/m\(^3\), respectively, the thickness of the mountain root (r1) is km. (Answer in integer)