Question:

If retardation produced by air resistance of projectile is one-tenth of acceleration due to gravity, the time to reach maximum height:

Updated On: Feb 28, 2024
  • decreases by 11 percent
  • increases by 11 percent
  • decreases by 90 percent
  • increases by 90 percent
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The Correct Option is C

Solution and Explanation

Suppose $t_{0}$ be the time to reach maximum height in the absence of air resistance, then from the relation $t_{0}=\frac{u \sin \alpha}{g}$ ...(1) when $a$ is retardation caused by air resistance, then total retardation will be $g+a$ $t_{1}=\frac{u \sin \alpha}{g +a}=\frac{u \sin \alpha}{g+\left(\frac{1}{10}\right) g}$ $=\frac{10 u \sin \alpha}{11 g}$ ...(2) Now from equations (1) and (2), we have $t_{1}=\frac{10}{11} t_{0}$ or $t_{1}=90 \% t_{0}$ Time will decrease by $90 \%$.
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration