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if q is the inverse point of p 1 1 with respect to
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If \( Q \) is the inverse point of \( P(-1, 1) \) with respect to the circle \( x^2 + y^2 - 2x + 2y = 0 \), then the line containing \( Q \) is:
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Inverse points with respect to a circle satisfy the condition: \( \vec{CP} \cdot \vec{CQ} = r^2 \), where \( C \) is the center of the circle.
AP EAPCET - 2025
AP EAPCET
Updated On:
Jun 4, 2025
\(x - 3y - 2 = 0\)
\(x - y + 1 = 0\)
\(x + y - 2 = 0\)
\(2x - 3y + 5 = 0\)
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