The correct answer is (D):
Let p3 = q4 = r5 = s6 = k
p = k1/3, q = k1/4, r = k1/5, s = k1/6
pqr = k(20+15+12/60) = k47/60
logs(pqr) = logk1/6k47/60
= (47/60×6)logkK
= 47/10
The product of all solutions of the equation \(e^{5(\log_e x)^2 + 3 = x^8, x > 0}\) , is :