Question:
If N and x are positive integers such that NN= 2160 and N2+2N is an integral multiple of 2x, then the largest possible x is
If N and x are positive integers such that NN= 2160 and N2+2N is an integral multiple of 2x, then the largest possible x is
Updated On: Sep 30, 2024
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Correct Answer: 10
Solution and Explanation
Given NN = 2160 = 25×32
= (25)32 ⇒ NN = 3232
⇒ N = 32
N2+2N = 322 + 232
⇒ (25)2+232
⇒ 210+232
= 210(1+222)
Or x is 10
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