To determine the number of possible relations between two finite sets, we analyze their Cartesian product and subsets.
1. Given Information:
- Set A has $p$ elements: $n(A) = p$
- Set B has $q$ elements: $n(B) = q$
2. Cartesian Product:
The Cartesian product $A × B$ contains all ordered pairs:
$ A × B = \{(a,b) \mid a \in A, b \in B\} $
Number of elements in $A × B$ is:
$ n(A × B) = p × q = pq $
3. Subsets of Cartesian Product:
For any set with $k$ elements, there are $2^k$ possible subsets.
Thus, $A × B$ has:
$ 2^{pq} $ possible subsets
4. Relations as Subsets:
Every relation from A to B corresponds to a subset of $A × B$.
Therefore, the number of possible relations equals the number of subsets.
Final Result:
The total number of relations from set A to set B is: $ 2^{pq} $
To determine the number of relations from set \( A \) to set \( B \), we need to understand the concept of relations between two sets.
Given sets \( A \) and \( B \) with cardinalities \( n(A)=p \) and \( n(B)=q \), a relation from \( A \) to \( B \) is a subset of the Cartesian product \( A \times B \).
The Cartesian product \( A \times B \) consists of all possible ordered pairs \((a,b)\) where \( a \in A \) and \( b \in B \). The total number of such ordered pairs is given by the product \( p \times q \) or simply \( pq \).
Each element of this Cartesian product can either be in a subset or not. Hence, for each of the \( pq \) elements, there are 2 choices (include it or exclude it in a relation).
Therefore, the total number of possible subsets (relations) is \( 2^{pq} \).
Thus, the number of relations from set \( A \) to set \( B \) is \( 2^{pq} \).
The shaded region in the Venn diagram represents
A solid cylinder of mass 2 kg and radius 0.2 m is rotating about its own axis without friction with angular velocity 5 rad/s. A particle of mass 1 kg moving with a velocity of 5 m/s strikes the cylinder and sticks to it as shown in figure.
The angular velocity of the system after the particle sticks to it will be: