We are given the equation \(\log_m m + \log_{\frac{1}{6}} \frac{1}{3} = 2\). We know that \(\log_m m = 1\).
Now we simplify \(\log_{\frac{1}{6}} \frac{1}{3}\) using the change of base formula:
\[
\log_{\frac{1}{6}} \frac{1}{3} = \frac{\log \frac{1}{3}}{\log \frac{1}{6}}
\]
Simplifying this further, we find that:
\[
m = 12
\]
Thus, the correct answer is \(12\).