The correct answer is (D):5+log3a = 23 = 8 ⇒ a = 27Similarly, 4a+12+log2b = 53 = 125since a = 27, 4(27)+12+log2b = 125 ⇒ b = 32a + b = 59.
The product of all solutions of the equation \(e^{5(\log_e x)^2 + 3 = x^8, x > 0}\) , is :