Question:
If lines \(\frac{x-1}{-3}=\frac{y-2}{2k}=\frac{z-3}{2}\) and \(\frac{x-1}{3k}=\frac{y-5}{1}=\frac{z-6}{-5}\) are mutually perpendicular then k is equal to
If lines \(\frac{x-1}{-3}=\frac{y-2}{2k}=\frac{z-3}{2}\) and \(\frac{x-1}{3k}=\frac{y-5}{1}=\frac{z-6}{-5}\) are mutually perpendicular then k is equal to
Updated On: Apr 26, 2024
- \(-\frac{10}{7}\)
- \(-\frac{7}{10}\)
- -10
- -7
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The Correct Option is A
Solution and Explanation
The correct answer is Option (A) : \(-\frac{10}{7}\)
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