If kinetic energy of a body is increased by 300\%, then the percentage change in momentum will be
Show Hint
- 100\%
- 150\%
- 265\%
- 73.2\%
The Correct Option is A
Solution and Explanation
Kinetic energy is related to momentum by the formula: \[ K.E. = \frac{p^2}{2m} \] where \( p \) is the momentum and \( m \) is the mass. If the kinetic energy is increased by 300\%, the new kinetic energy becomes 4 times the original kinetic energy. Since the kinetic energy is proportional to the square of momentum, the momentum will increase by a factor of 2. Therefore, the percentage change in momentum is: \[ \frac{2p - p}{p} \times 100 = 100\% \] Thus, the correct answer is (A).
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