Question:

If $*$ is defined by $a*b$ = $a - b^2$ and $\oplus$ is defined by $\oplus$ = $a^2 + b$, where a and b are integers, then ($3 \oplus 4) * 5$ is equal to

Updated On: Jun 7, 2024
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The Correct Option is C

Solution and Explanation

Given, $a^{*}b =a-b^{2}\,\,\,\,\,\dots(i)$
and $a \oplus b=a^{2}+b \,\,\,\,\,\dots(ii)$
where, $a$ and $b$ are integers.
Then, $(3 \oplus 4)^{*} 5 =\left\{(3)^{2}+4\right\}^{*} 5$
$=(9+4)^{*} 5=13^{*} 5 $
$=13-(5)^{2}=13-25=-12$
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Concepts Used:

Functions

A function is a relation between a set of inputs and a set of permissible outputs with the property that each input is related to exactly one output. Let A & B be any two non-empty sets, mapping from A to B will be a function only when every element in set A has one end only one image in set B.

Kinds of Functions

The different types of functions are - 

One to One Function: When elements of set A have a separate component of set B, we can determine that it is a one-to-one function. Besides, you can also call it injective.

Many to One Function: As the name suggests, here more than two elements in set A are mapped with one element in set B.

Moreover, if it happens that all the elements in set B have pre-images in set A, it is called an onto function or surjective function.

Also, if a function is both one-to-one and onto function, it is known as a bijective. This means, that all the elements of A are mapped with separate elements in B, and A holds a pre-image of elements of B.

Read More: Relations and Functions