To solve the given integral equation, we need to understand and simplify the expression and find the product \( AB \). The integral is:
\[\int \frac{\sin^{\frac{2}{3}} x + \cos^{\frac{2}{3}} x}{\sqrt{\sin^{\frac{1}{3}} x \cos^{\frac{1}{3}} x \sin(x - \theta)}} \, dx = A \sqrt{\cos \theta \tan x - \sin \theta} + B \sqrt{\cos \theta \cot x + \sin(x - \theta)} + C\]Firstly, examine the expression under the integral. Simplifying or transforming parts of the integral might make it easier to evaluate or compare with the right-hand side:
Let's simplify using appropriate substitutions:
Upon simplifying, you can express the solution components separately, leading to the following steps:
Finally, calculate \( AB \) using the derived values:
\[AB = 8 \csc(2\theta)\]Therefore, the correct answer for \( AB \) is \( 8 \csc(2\theta) \).
Let \( \alpha, \beta \) be the roots of the equation \( x^2 - ax - b = 0 \) with \( \text{Im}(\alpha) < \text{Im}(\beta) \). Let \( P_n = \alpha^n - \beta^n \). If \[ P_3 = -5\sqrt{7}, \quad P_4 = -3\sqrt{7}, \quad P_5 = 11\sqrt{7}, \quad P_6 = 45\sqrt{7}, \] then \( |\alpha^4 + \beta^4| \) is equal to:
A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field \( B \) exists into the page. The bar starts to move from the vertex at time \( t = 0 \) with a constant velocity. If the induced EMF is \( E \propto t^n \), then the value of \( n \) is _____. 