Given:
Two circles have arcs of equal length that subtend angles of 30° and 78° at their centers.
Step 1: Recall the arc length formula.
Arc length \( l = r \theta \), where \( r \) is radius and \( \theta \) is in radians.
Step 2: Convert angles to radians.
First angle: \( 30° = \frac{\pi}{6} \) radians
Second angle: \( 78° = \frac{13\pi}{30} \) radians
Step 3: Set arc lengths equal.
\( r_1 \cdot \frac{\pi}{6} = r_2 \cdot \frac{13\pi}{30} \)
Step 4: Solve for the ratio \( \frac{r_1}{r_2} \).
\( \frac{r_1}{r_2} = \frac{13\pi/30}{\pi/6} = \frac{13}{5} \)
Option Analysis:
(A) \( \frac{5}{13} \) - Inverse of correct ratio
(B) \( \frac{13}{5} \) - Correct
(C) \( \frac{13}{4} \) - Incorrect
(D) \( \frac{4}{1} \) - Incorrect
Final Answer: \(\boxed{B}\)
The length of an arc is given by $l = r\theta$, where $r$ is the radius and $\theta$ is the angle subtended (in radians).
For the two circles: $\frac{r_1}{r_2} = \frac{\theta_2}{\theta_1}$
Convert degrees to radians: $\theta_1 = 30^\circ = \frac{\pi}{6}, \quad \theta_2 = 78^\circ = \frac{13\pi}{30}$. $\frac{r_1}{r_2} = \frac{\frac{13\pi}{30}}{\frac{\pi}{6}} = \frac{13}{5}$.