Question:

If frequencies are \( (v - 1) \) and \( (v + 2) \), then find the value of beats.

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Beat frequency is calculated as the absolute difference between two close frequencies: \( f_{\text{beat}} = |f_1 - f_2| \).
Updated On: Apr 23, 2025
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The Correct Option is C

Solution and Explanation

The beat frequency is given by the absolute difference of the two frequencies: \[ f_{\text{beat}} = |f_1 - f_2| \] Given: \[ f_1 = v - 1, \quad f_2 = v + 2 \] Now calculate the beat frequency: \[ f_{\text{beat}} = |(v + 2) - (v - 1)| = |v + 2 - v + 1| = |3| = 3 \] So, the number of beats per second is: \[ \boxed{3} \]
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