Question:

1010 forks are arranged in increasing order of frequency in such a way that any two nearest tuning forks produce 44 beats/sec. The highest frequency is twice of the lowest. Possible highest and the lowest frequencies (in HzHz ) are

Updated On: Jan 30, 2025
  • 80 and 40
  • 100 and 50
  • 44 and 22
  • 72 and 36
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The Correct Option is D

Solution and Explanation

Using nLast =nFirst +(N1)xn_{\text {Last }}=n_{\text {First }}+(N-1) x
where N=N = Number of tuning forks in series
x=x= beat frequency between two successive forks
2n=n+(101)×4\Rightarrow 2 n=n+(10-1) \times 4
n=36Hz \Rightarrow n=36 \,H z
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Concepts Used:

Beats

What is Beat Frequency?

Let’s see from fig.m, the frequency of a pink-colored wave is f1, and that of a green-colored wave is f2. So, the frequency of the beat is the difference between these two, which is:

                               fBEATS  = |f1 - f2|

Interference and Beats

When two or more waves travelling in a medium meet, the resulting phenomenon is called interference and beats are an excellent example of the phenomenon of interference. 

What is Interference?

When two or more waves travelling in a medium meet, the resulting phenomenon is called interference and beats are an excellent example of the phenomenon of interference.

The Application of Beats:

  • Beats are used in determining the unknown frequency
  • Beats are used in determining the existence of poisonous gases in mines.