Question:
$10$ forks are arranged in increasing order of frequency in such a way that any two nearest tuning forks produce $4$ beats/sec. The highest frequency is twice of the lowest. Possible highest and the lowest frequencies (in $Hz$ ) are
$10$ forks are arranged in increasing order of frequency in such a way that any two nearest tuning forks produce $4$ beats/sec. The highest frequency is twice of the lowest. Possible highest and the lowest frequencies (in $Hz$ ) are
Updated On: Jan 30, 2025
- 80 and 40
- 100 and 50
- 44 and 22
- 72 and 36
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The Correct Option is D
Solution and Explanation
Using $n_{\text {Last }}=n_{\text {First }}+(N-1) x$
where $N =$ Number of tuning forks in series
$x=$ beat frequency between two successive forks
$\Rightarrow 2 n=n+(10-1) \times 4$
$ \Rightarrow n=36 \,H z$
where $N =$ Number of tuning forks in series
$x=$ beat frequency between two successive forks
$\Rightarrow 2 n=n+(10-1) \times 4$
$ \Rightarrow n=36 \,H z$
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Concepts Used:
Beats
What is Beat Frequency?
Let’s see from fig.m, the frequency of a pink-colored wave is f1, and that of a green-colored wave is f2. So, the frequency of the beat is the difference between these two, which is:
fBEATS = |f1 - f2|
Interference and Beats
When two or more waves travelling in a medium meet, the resulting phenomenon is called interference and beats are an excellent example of the phenomenon of interference.
What is Interference?
When two or more waves travelling in a medium meet, the resulting phenomenon is called interference and beats are an excellent example of the phenomenon of interference.
The Application of Beats:
- Beats are used in determining the unknown frequency
- Beats are used in determining the existence of poisonous gases in mines.