Question:

If z5iz5i=1 \frac{|z - 5i|}{|z - 5i|} = 1 , then

Show Hint

For complex numbers, if za=r |z - a| = r , the modulus represents the distance of z z from point a a on the complex plane.
Updated On: Mar 7, 2025
  • Re(z)=0 {Re}(z) = 0
  • z=10 |z| = 10
  • z=25 |z| = 25
  • z=5 |z| = 5
  • Im(z)=0 {Im}(z) = 0
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is

Solution and Explanation

We are given the equation: z5iz5i=1 \frac{|z - 5i|}{|z - 5i|} = 1 The expression z5iz5i \frac{|z - 5i|}{|z - 5i|} represents the ratio of the magnitude of z5i z - 5i to itself. This ratio is always 1 unless z5i=0 |z - 5i| = 0 , in which case the ratio would be undefined. Thus, the condition z5iz5i=1 \frac{|z - 5i|}{|z - 5i|} = 1 implies that z5i0 |z - 5i| \neq 0 , or equivalently: z5i. z \neq 5i. This means the point z z cannot be at 5i 5i on the imaginary axis. Now, we consider the nature of z z . Let z=x+iy z = x + iy , where x=Re(z) x = {Re}(z) is the real part and y=Im(z) y = {Im}(z) is the imaginary part of z z . The expression z5i |z - 5i| represents the distance between the complex number z=x+iy z = x + iy and the point 5i 5i , which is (0,5) (0, 5) on the imaginary axis. The distance formula gives: z5i=x2+(y5)2. |z - 5i| = \sqrt{x^2 + (y - 5)^2}. For the ratio z5iz5i=1 \frac{|z - 5i|}{|z - 5i|} = 1 to hold, the complex number z z must be such that the imaginary part y y must be equal to zero because if the imaginary part were non-zero, the expression would not yield a ratio of 1. 
Hence, the condition simplifies to: Im(z)=0. {Im}(z) = 0.  
Therefore, the imaginary part of z z must be zero, which corresponds to option (E). 
Thus, the correct answer is Im(z)=0 \boxed{{Im}(z) = 0} , corresponding to option (E).

Was this answer helpful?
0
0

Top Questions on Integration

View More Questions