The correct option is(D): none of these.
To find the limit of the function f(x)=[x]sin(x) as x approaches 0, let's analyze the behavior of the function as x approaches 0 from both the left and the right sides.
As x approaches 0 from the right side (x>0), the greatest integer function [x] is always 0, since all values of x between 0 and 1 are rounded down to 0. Therefore, the function becomes f(x)=0sin(x), which is undefined.
As x approaches 0 from the left side (x<0), the greatest integer function [x] is again 0, for the same reason as above. So, the function becomes f(x)=0sin(x), which is still undefined.
Since the function is undefined as x approaches 0 from both sides, the limit of f(x) as x approaches 0 does not exist. Therefore, the correct answer is "none of these."
In mathematical terms, this can be formally expressed as:
limx→0f(x)=undefined.
Let the function, \(f(x)\) = \(\begin{cases} -3ax^2 - 2, & x < 1 \\a^2 + bx, & x \geq 1 \end{cases}\) Be differentiable for all \( x \in \mathbb{R} \), where \( a > 1 \), \( b \in \mathbb{R} \). If the area of the region enclosed by \( y = f(x) \) and the line \( y = -20 \) is \( \alpha + \beta\sqrt{3} \), where \( \alpha, \beta \in \mathbb{Z} \), then the value of \( \alpha + \beta \) is:
If \( y = e^{{2}\log_e t} \) and \( x = \log_3(e^{t^2}) \), then \( \frac{dy}{dx} \) is equal to:
A function is said to be continuous at a point x = a, if
limx→a
f(x) Exists, and
limx→a
f(x) = f(a)
It implies that if the left hand limit (L.H.L), right hand limit (R.H.L) and the value of the function at x=a exists and these parameters are equal to each other, then the function f is said to be continuous at x=a.
If the function is undefined or does not exist, then we say that the function is discontinuous.
Conditions for continuity of a function: For any function to be continuous, it must meet the following conditions: