We are given the functions \( f(x) = x + 8 \) and \( g(x) = 2x^2 \), and we are asked to find \( (g \circ f)(x) \), which means \( g(f(x)) \).
By the definition of composition of functions, we substitute \( f(x) \) into \( g(x) \). Therefore, we have: \[ (g \circ f)(x) = g(f(x)) = g(x + 8). \]
Now, substitute \( x + 8 \) into the expression for \( g(x) \): \[ g(x + 8) = 2(x + 8)^2. \]
Thus, \( (g \circ f)(x) = 2(x + 8)^2 \).
Thus, the correct answer is \( \boxed{2(x + 8)^2} \), corresponding to option (B).
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
If the function \[ f(x) = \begin{cases} \frac{2}{x} \left( \sin(k_1 + 1)x + \sin(k_2 -1)x \right), & x<0 \\ 4, & x = 0 \\ \frac{2}{x} \log_e \left( \frac{2 + k_1 x}{2 + k_2 x} \right), & x>0 \end{cases} \] is continuous at \( x = 0 \), then \( k_1^2 + k_2^2 \) is equal to: