Question:

If α,β\alpha,\beta are the zeroes of the quadratic polynomial ax2+bx+cax^2 + bx+ca0a ≠0 then α2+β2=\alpha^2+\beta^2=

Updated On: May 7, 2024
  • 1a2(b2+2ac)\frac{1}{a^2}(b^2+2ac)
  • 1a2(c2+2ab)\frac{1}{a^2}(c^2+2ab)
  • 1a2(b22ac)\frac{1}{a^2}(b^2-2ac)
  • 1a2(c22ab)\frac{1}{a^2}(c^2-2ab)
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The Correct Option is C

Solution and Explanation

The correct option is (C): 1a2(b22ac)\frac{1}{a^2}(b^2-2ac)
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