Question:

If $\alpha$ and $\beta$ are the roots of $x^2 - ax + b^2 = 0$, then $\alpha^2 + \beta^2$ is equal to

Updated On: Sep 4, 2024
  • $a^2-2b^2$
  • $2a^2 -b^2$
  • $a^2 - b^2$
  • $a^2 + b^2$
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The Correct Option is A

Solution and Explanation

The correct answer is A:\(a^2-2b^2\)
Given that, \(\alpha\) and \(\beta\) are the roots of \(x^{2}-a x+b^{2}=0\).
\(\alpha+\beta=\frac{-(-a)}{1}=a\)
and \(\alpha \beta=\frac{b^{2}}{1}=b^{2}\)
\((\alpha+\beta)^2=\alpha^2+\beta^2+2\alpha\beta\)
Now, \(\alpha^{2}+\beta^{2} =(\alpha+\beta)^{2}-2 \alpha \beta\)
\(\alpha^2+\beta^2\)\(=a^{2}-2 b^{2}\)
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Concepts Used:

Complex Numbers and Quadratic Equations

Complex Number: Any number that is formed as a+ib is called a complex number. For example: 9+3i,7+8i are complex numbers. Here i = -1. With this we can say that i² = 1. So, for every equation which does not have a real solution we can use i = -1.

Quadratic equation: A polynomial that has two roots or is of the degree 2 is called a quadratic equation. The general form of a quadratic equation is y=ax²+bx+c. Here a≠0, b and c are the real numbers.