Question:

If an ideal engine needs to transmit a torque of 200 Nm to maintain a rotor at a uniform angular speed of 300 rads1^{-1}, then the power required for the engine is:

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Power transmitted by a rotating body is the product of the torque and angular velocity. Ensure that the units of torque and angular velocity are consistent to calculate the power in watts or kilowatts.
Updated On: Mar 11, 2025
  • 30 kW
  • 60 kW
  • 90 kW
  • 150 kW
  • 300 kW
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The Correct Option is B

Solution and Explanation

The power (P P ) transmitted by a torque is given by the formula: P=τω P = \tau \omega where: - P P is the power,
- τ \tau is the torque,
- ω \omega is the angular velocity.
Given: - Torque τ=200Nm \tau = 200 \, {Nm} ,
- Angular velocity ω=300rads1 \omega = 300 \, {rads}^{-1} .
Substituting these values into the formula for power: P=200×300=60000W=60kW P = 200 \times 300 = 60000 \, {W} = 60 \, {kW} Thus, the power required for the engine is: 60kW \boxed{60 \, {kW}}
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