Question

If an aqueous solution of NaF is electrolyzed between insert electrodes, the product obtained at anode is

• A. O₂
• B. F₂
• C. H₂
• D. Na

Answer 1

The Correct Option is A

In the electrolysis of an aqueous solution of NaF, the reactions at the anode and cathode are important. The anode is where oxidation occurs, and the cathode is where reduction takes place. At the anode, water molecules can also be oxidized because \( \text{OH}^- \) ions are present. The possible oxidation reactions at the anode are:
1. Oxidation of \( \text{OH}^- \) to \( \text{O}_2 \): \[ 4\text{OH}^- \rightarrow \text{O}_2 + 2\text{H}_2\text{O} + 4e^- \] 2. Oxidation of \( \text{F}^- \) to \( \text{F}_2 \): \[ 2\text{F}^- \rightarrow \text{F}_2 + 2e^- \] However, oxygen gas (\( \text{O}_2 \)) is generally produced at the anode in aqueous electrolysis, as the oxidation of water is easier than the oxidation of fluoride ions under normal conditions. Thus, the product obtained at the anode is \( \text{O}_2 \).

The correct option is (A) : \(O_2\)