To find the perimeter of triangle \( ABC \), we first determine the lengths of the sides \( AB \), \( BC \), and \( CA \). The perimeter is the sum of these lengths. Step 1: Find the length of \( AB \) The vector \( AB \) is given by: \[ AB = 2i + 3j - 6k. \] The length of \( AB \) is: \[ |AB| = \sqrt{2^2 + 3^2 + (-6)^2} = \sqrt{4 + 9 + 36} = \sqrt{49} = 7. \] Step 2: Find the length of \( BC \) The vector \( BC \) is given by: \[ BC = 6i - 2j + 3k. \] The length of \( BC \) is: \[ |BC| = \sqrt{6^2 + (-2)^2 + 3^2} = \sqrt{36 + 4 + 9} = \sqrt{49} = 7. \] Step 3: Find the length of \( CA \) The vector \( CA \) is the negative of the sum of \( AB \) and \( BC \): \[ CA = -(AB + BC) = -[(2i + 3j - 6k) + (6i - 2j + 3k)] = -(8i + j - 3k) = -8i - j + 3k. \] The length of \( CA \) is: \[ |CA| = \sqrt{(-8)^2 + (-1)^2 + 3^2} = \sqrt{64 + 1 + 9} = \sqrt{74}. \] Step 4: Compute the perimeter The perimeter of triangle \( ABC \) is the sum of the lengths of its sides: \[ \text{Perimeter} = |AB| + |BC| + |CA| = 7 + 7 + \sqrt{74} = 14 + \sqrt{74}. \] Final Answer: \[ \boxed{\sqrt{74} + 14} \]
Which of the following are ambident nucleophiles?
[A.] CN$^{\,-}$
[B.] CH$_{3}$COO$^{\,-}$
[C.] NO$_{2}^{\,-}$
[D.] CH$_{3}$O$^{\,-}$
[E.] NH$_{3}$
Identify the anomers from the following.

The standard Gibbs free energy change \( \Delta G^\circ \) of a cell reaction is \(-301 { kJ/mol}\). What is \( E^\circ \) in volts?
(Given: \( F = 96500 { C/mol}\), \( n = 2 \))