Question:

If A.M. and G.M. of roots of a quadratic equation are $5$ and $4$ respectively, then the quadratic equation is:

Updated On: Dec 26, 2024
  • $x^2 - 10x - 16 = 0$
  • $x^2 + 10x + 16 = 0$
  • $x^2 + 10x - 16 = 0$
  • $x^2 - 10x + 16 = 0$
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The Correct Option is D

Solution and Explanation

Let the roots be $\alpha$ and $\beta$.

Then: A.M. $= \frac{\alpha + \beta}{2} = 5 \implies \alpha + \beta = 10$. G.M. $= \sqrt{\alpha\beta} = 4 \implies \alpha\beta = 16$. 

The quadratic equation is $x^2 - (\alpha + \beta)x + \alpha\beta = 0$, i.e., $x^2 - 10x + 16 = 0$. 

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