We are given that \( A \) is an orthogonal matrix. By definition, a matrix \( A \) is orthogonal if:
\[ A^T A = A A^T = I \]
Where \( I \) is the identity matrix. The inverse of an orthogonal matrix is also orthogonal. Specifically, for an orthogonal matrix \( A \), we have:
\[ A^{-1} = A^T \]
This means the inverse of an orthogonal matrix is also orthogonal, as its transpose is its inverse.
Thus, the correct answer is option (C), Orthogonal.
Let $ A = \begin{bmatrix} 2 & 2 + p & 2 + p + q \\4 & 6 + 2p & 8 + 3p + 2q \\6 & 12 + 3p & 20 + 6p + 3q \end{bmatrix} $ If $ \text{det}(\text{adj}(\text{adj}(3A))) = 2^m \cdot 3^n, \, m, n \in \mathbb{N}, $ then $ m + n $ is equal to: