Question:

If a cycle wheel of radius $4\,m $ completes one revolution in two seconds. Then acceleration of the cycle will be

Updated On: Jul 27, 2022
  • $\pi ^{2}m/s^{2}$
  • $ 2\pi ^{2}m/s^{2}$
  • $ 4\pi ^{2}m/s^{2}$
  • $ 8\pi \,\,m/s^{2}$
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The Correct Option is C

Solution and Explanation

Here : Frequency of revolution $t=\frac{1}{2} rev / \sec$ Radius of wheel of cycle $r=4\, m$ The acceleration of the wheel is given by $=r \omega^{2}=r \times(2 \pi f)^{2}$ $=4 \times\left(2 \times \pi \times \frac{1}{2}\right)^{2}$ $=4 \pi^{2} m / s ^{2}$
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration