Number of remaining children = 24 - 4 = 20
Let the number of sweets which each of the 20 students will get, be x.
The following table is obtained.
Number of students | 24 | 20 |
---|---|---|
Number of sweets | 5 | x |
If the number of students is lesser, then each student will get more number of sweets.
Since this is a case of inverse proportion,
\(24 × 5 = 20 × x\)
\(x= \frac{24 × 5}{20}\)
Hence, each student will get 6 sweets.
As the number of children increases, the number of sweets each child gets decreases.
So, \(x \times y = \text{constant}\)
Given:\( x_1 = 24\) and \(y_1 = 5\)
\(x_2 = 20\) and \(y_2 = ?\)
Since\( x_1 \times y_1 = x_2 \times y_2\)
\(y_2 = \frac{x_1 \times y_1}{x_2} = \frac{24 \times 5}{20} = 6\)
So, each child gets 6 sweets.
Number of spokes | 4 | 6 | 8 | 10 | 12 |
---|---|---|---|---|---|
Angle between a pair of consecutive spokes | 90° | 60° | … | … | … |
(i) Are the number of spokes and the angles formed between the pairs of consecutive spokes in inverse proportion?
(ii) Calculate the angle between a pair of consecutive spokes on a wheel with 15 spokes.
(iii) How many spokes would be needed, if the angle between a pair of consecutive spokes is 40°?