Question:

If a box of sweets is divided among 24 children, they will get 5 sweets each. How many would each get, if the number of the children is reduced by 4?

Updated On: Jun 8, 2024
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Approach Solution - 1

Number of remaining children = 24 - 4 = 20 
Let the number of sweets which each of the 20 students will get, be x. 
The following table is obtained.

Number of students2420
Number of sweets5x

If the number of students is lesser, then each student will get more number of sweets.
Since this is a case of inverse proportion,
\(24 × 5 = 20 × x\)
\(x= \frac{24 × 5}{20}\)
Hence, each student will get 6 sweets.

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Approach Solution -2

As the number of children increases, the number of sweets each child gets decreases.
So, \(x \times y = \text{constant}\)

Given:\( x_1 = 24\) and \(y_1 = 5\)
\(x_2 = 20\) and \(y_2 = ?\)

Since\( x_1 \times y_1 = x_2 \times y_2\)
\(y_2 = \frac{x_1 \times y_1}{x_2} = \frac{24 \times 5}{20} = 6\)
So, each child gets 6 sweets.

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