The adjugate of \( A \), denoted \( \text{adj}(A) \), is given by the formula: \[ \text{adj}(A) = \begin{bmatrix} 5 & -7 \\ -2 & 3 \end{bmatrix} \] Now, \( A^2 (\text{adj} A) = A \), as per the property of matrices where \( A^2 \times \text{adj}(A) = \det(A) \times A \).
Here, \( \det(A) = (3 \times 5) - (7 \times 2) = 15 - 14 = 1 \), so the result is \( A \).
Draw a rough sketch for the curve $y = 2 + |x + 1|$. Using integration, find the area of the region bounded by the curve $y = 2 + |x + 1|$, $x = -4$, $x = 3$, and $y = 0$.
If the function \[ f(x) = \begin{cases} \frac{2}{x} \left( \sin(k_1 + 1)x + \sin(k_2 -1)x \right), & x<0 \\ 4, & x = 0 \\ \frac{2}{x} \log_e \left( \frac{2 + k_1 x}{2 + k_2 x} \right), & x>0 \end{cases} \] is continuous at \( x = 0 \), then \( k_1^2 + k_2^2 \) is equal to: