Step 1: Characteristic Equation. We substitute \( A \) into the given equation: \[ A^2 - kA - 5I = 0 \] Calculating \( A^2 \):
\[A^2 = \begin{bmatrix} 1 & 3\\ 3 & 4 \end{bmatrix} \times \begin{bmatrix} 1 & 3 \\ 3 & 4 \end{bmatrix} = \begin{bmatrix} 10 & 15 \\ 15 & 25 \end{bmatrix}\]Using matrix identity \(I = \begin{bmatrix} 1 & 0 \\ 0 & 1 \end{bmatrix}\), substituting in the equation and solving for \( k \), we obtain: \[ k = 5 \]
Conclusion: Thus, the required value is \( 5 \), which corresponds to option \( \mathbf{(B)} \).
Balance Sheet of Madhavan, Chatterjee and Pillai as at 31st March, 2024
| Liabilities | Amount (₹) | Assets | Amount (₹) |
|---|---|---|---|
| Creditors | 1,10,000 | Cash at Bank | 4,05,000 |
| Outstanding Expenses | 17,000 | Stock | 2,20,000 |
| Mrs. Madhavan’s Loan | 2,00,000 | Debtors | 95,000 |
| Chatterjee’s Loan | 1,70,000 | Less: Provision for Doubtful Debts | (5,000) |
| Capitals: | Madhavan – 2,00,000 | Land and Building | 1,82,000 |
| Chatterjee – 1,00,000 | Plant and Machinery | 1,00,000 | |
| Pillai – 2,00,000 | |||
| Total | 9,97,000 | Total | 9,97,000 |


Arrange the following compounds in increasing order of their boiling points:
