Question:

If \(A=\begin{bmatrix}1&0 \\ 0&1\end{bmatrix}\), then the value of \(A^{25}\) is

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Raising the identity to any power gives the identity back: \(I^n=I\).
  • \(25A\)
  • \(24A\)
  • \(2A\)
  • \(A\)
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The Correct Option is D

Solution and Explanation

The given matrix is the identity \(I_2\). Identity is the multiplicative neutral element: \[ I_2^n=I_2\text{for any positive integer }n. \] Therefore, \[ A^{25}=I_2^{25}=I_2=A. \]
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