If\( \vec{a}=\vec{b}+\vec{c}\), then is it true that |\(\vec{a}\)|=|\(\vec{b}\)|+|\(\vec{c}\)| ? justify your answer.
In \(△ABC\),let \(\overrightarrow{CB}=\vec{a},\overrightarrow{CA}=\vec{b},\)and \(\overrightarrow{AB}=\vec{c}\)(as shown in the following figure).
Now,by the triangle law of vector addition,we have \(\vec{a}=\vec{b}+\vec{c}\).
It is clearly known that |\(\vec{a}\)|,|\(\vec{b}\)|,and |\(\vec{c}\)|represent the sides of \(△ABC.\)
Also,it is known that the sum of the lengths of any two sides of a triangle is greater than the third side.
∴|\(\vec{a}\)|<|\(\vec{b}\)|+|\(\vec{c}\)|
|Hence,it is not true that |\(\vec{a}\)|=|\(\vec{b}\)|+|\(\vec{c}\)|.
If \( X \) is a random variable such that \( P(X = -2) = P(X = -1) = P(X = 2) = P(X = 1) = \frac{1}{6} \), and \( P(X = 0) = \frac{1}{3} \), then the mean of \( X \) is
List-I | List-II |
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(A) 4î − 2ĵ − 4k̂ | (I) A vector perpendicular to both î + 2ĵ + k̂ and 2î + 2ĵ + 3k̂ |
(B) 4î − 4ĵ + 2k̂ | (II) Direction ratios are −2, 1, 2 |
(C) 2î − 4ĵ + 4k̂ | (III) Angle with the vector î − 2ĵ − k̂ is cos⁻¹(1/√6) |
(D) 4î − ĵ − 2k̂ | (IV) Dot product with −2î + ĵ + 3k̂ is 10 |