Question:

If \(|\vec{a}\times\vec{b}|+|\vec{a}.\vec{b}|^2\)=144 and \(|\vec{a}|\) = 6, then \(|\vec{b}|\) is equal to

Updated On: Apr 3, 2024
  • 6
  • 3
  • 2
  • 4
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The Correct Option is C

Solution and Explanation

The correct answer is (C) : 2.
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