Question:

If \( A \) and \( B \) are two non-zero square matrices of the same order such that \[ (A + B)^2 = A^2 + B^2, \] then:

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For square matrices \( A \) and \( B \), the relation \( AB = -BA \) implies the matrices are anti-commutative.
Updated On: Jan 18, 2025
  • \( AB = O \)
  • \( AB = -BA \)
  • \( BA = O \)
  • \( AB = BA \)
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The Correct Option is B

Solution and Explanation

Expand the left-hand side of the given equation: \[ (A + B)^2 = A^2 + AB + BA + B^2. \] 

Equating both sides: \[ A^2 + AB + BA + B^2 = A^2 + B^2. \] 

Cancel \( A^2 \) and \( B^2 \): \[ AB + BA = 0. \]

Rearranging: \[ AB = -BA. \] 

Therefore, the correct answer is (B) \( AB = -BA \).

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