Step 1: Substitute values. \[ P(A|B) = \frac{0.15}{0.3} \]
Step 2: Simplify. \[ P(A|B) = 0.5 \]
Final Answer: \[ \boxed{0.5} \]
Of the 20 lightbulbs in a box, 2 are defective. An inspector will select 2 lightbulbs simultaneously and at random from the box. What is the probability that neither of the lightbulbs selected will be defective?