Question:

If \(a\) and \(b\) are negative, and \(c\) is positive, which of the following statements is/are true?
I) \(a - b < c - a\)
II) \(a + b < b + c\)  
III) \(b < c < a\)

Updated On: Aug 21, 2025
  • I only
  • II only
  • III only
  • II and III only
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The Correct Option is D

Solution and Explanation

Step 1 — Analyze Statement I: \(a - b < c - a\)
Rewrite inequality:
\(a - b < c - a\)
\(\Rightarrow a + a < c + b\)
\(\Rightarrow 2a < b + c\).

Since \(a < 0\), the left-hand side \(2a\) is negative. The right-hand side \(b + c\) may be negative or positive depending on values.
Example: \(a = -5, b = -3, c = 2\). Then LHS = -2, RHS = 7 → inequality true.
But if \(a = -1, b = -100, c = 1\). Then LHS = -2, RHS = -99 → inequality false.
Therefore, Statement I is not always true.

Step 2 — Analyze Statement II: \(a + b < b + c\)
Simplify:
\(a + b < b + c\)
\(\Rightarrow a < c\).
Since \(a < 0\) and \(c > 0\), this is always true.
Hence, Statement II is always true.

Step 3 — Analyze Statement III: \(b < c < a\)
This requires \(c < a\). But \(c\) is positive and \(a\) is negative, so a positive number cannot be less than a negative number.
Therefore, Statement III is false.

Final Answer: Only Statement II is correct.
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