Step 1: Determine the number of elements in sets \( A \) and \( B \).
The set \( A \) has 3 elements, and set \( B \) has 2 elements. The number of functions from set \( A \) to set \( B \) is given by the formula \( |B|^{|A|} \), where \( |A| \) and \( |B| \) represent the number of elements in sets \( A \) and \( B \), respectively.
Step 2: Apply the formula.
Substituting the values \( |A| = 3 \) and \( |B| = 2 \), we get: \[ 2^3 = 8 \]
Step 3: Conclusion.
Thus, the total number of functions is \( 8 \), which is the correct answer.
Let $R$ be a relation defined on the set $\{1,2,3,4\times\{1,2,3,4\}$ by \[ R=\{((a,b),(c,d)) : 2a+3b=3c+4d\} \] Then the number of elements in $R$ is
Let \(M = \{1, 2, 3, ....., 16\}\), if a relation R defined on set M such that R = \((x, y) : 4y = 5x – 3, x, y (\in) M\). How many elements should be added to R to make it symmetric.