If \(A = \{1, 2, 3, 4, 5, 6\}\), then the number of subsets of \(A\) which contain at least two elements is:
The total number of subsets of A is \(2^6 = 64\). The number of subsets with at least two elements is equal to the total number of subsets minus the number of subsets with zero elements (the empty set) and the number of subsets with one element.
Number of subsets with zero elements = 1 (the empty set)
Number of subsets with one element = 6 (one for each element)
Number of subsets with at least two elements = \(64 - 1 - 6 = 57\)
The total number of subsets of $ A $ is:
$$ 2^{|A|} = 2^6 = 64. $$
The number of subsets with 0 elements is:
$$ \binom{6}{0} = 1 \quad \text{(the empty set)}. $$
The number of subsets with 1 element is:
$$ \binom{6}{1} = 6. $$
Thus, the number of subsets with at least two elements is:
$$ 64 - 1 - 6 = 57. $$
Let \( S = \{p_1, p_2, \dots, p_{10}\} \) be the set of the first ten prime numbers. Let \( A = S \cup P \), where \( P \) is the set of all possible products of distinct elements of \( S \). Then the number of all ordered pairs \( (x, y) \), where \( x \in S \), \( y \in A \), and \( x \) divides \( y \), is _________.
Let \( A = \{1,2,3\} \). The number of relations on \( A \), containing \( (1,2) \) and \( (2,3) \), which are reflexive and transitive but not symmetric, is ______.
Let \( A = (1, 2, 3, \dots, 20) \). Let \( R \subseteq A \times A \) such that \( R = \{(x, y) : y = 2x - 7 \} \). Then the number of elements in \( R \) is equal to: