If $3x + 4y = 12$ and $x - y = 1$, what is the value of $x + y$?
24/7
25/4
25/7
23/7
From x − y = 1:
x = y + 1
Substituting x = y + 1 into 3x + 4y = 12:
3(y + 1) + 4y = 12 3y + 3 + 4y = 12 7y + 3 = 12 7y = 9 y = 9/7
Using x = y + 1:
x = (9/7) + 1 = (9/7) + (7/7) = 16/7
Adding the values:
x + y = (16/7) + (9/7) = 25/7
x + y = 25/7
Three distinct numbers are selected randomly from the set \( \{1, 2, 3, \dots, 40\} \). If the probability, that the selected numbers are in an increasing G.P. is \( \frac{m}{n} \), where \( \gcd(m, n) = 1 \), then \( m + n \) is equal to:
A board has 16 squares as shown in the figure. Out of these 16 squares, two squares are chosen at random. The probability that they have no side in common is: