Question:

If 279 g of aniline is reacted with one equivalent of benzenediazonium chloride, the mximum amount of aniline yellow formed will be _____ g. (nearest integer)
(consider complete conversion)

Updated On: Mar 21, 2025
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Correct Answer: 591

Solution and Explanation

The balanced reaction is:
C6H5NH2+C6H5N2+ClC6H5N=NC6H5(Aniline yellow).\text{C}_6\text{H}_5\text{NH}_2 + \text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- \rightarrow \text{C}_6\text{H}_5\text{N} = \text{N} -\text{C}_6\text{H}_5 \, (\text{Aniline yellow}).
Given:
Molar mass of aniline=93g/mol,Given mass=279g.\text{Molar mass of aniline} = 93 \, \text{g/mol}, \quad \text{Given mass} = 279 \, \text{g}.
Moles of aniline:
n=27993=3mol.n = \frac{279}{93} = 3 \, \text{mol}.
Mass of aniline yellow:
Molar mass of product=197g/mol.\text{Molar mass of product} = 197 \, \text{g/mol}.
Mass=3197=591g.\text{Mass} = 3 \cdot 197 = 591 \, \text{g}.
Final Answer:
591g.591 \, \text{g}.

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