We are given the equation:
\[
2^{x+6} = 8^{x+1}
\]
Step 1: Express 8 as a power of 2:
\[
8 = 2^3
\]
So the equation becomes:
\[
2^{x+6} = (2^3)^{x+1}
\]
Step 2: Simplify the right-hand side:
\[
2^{x+6} = 2^{3(x+1)}
\]
\[
2^{x+6} = 2^{3x+3}
\]
Step 3: Since the bases are the same, we can equate the exponents:
\[
x + 6 = 3x + 3
\]
Step 4: Solve for \( x \):
\[
x + 6 = 3x + 3
\]
\[
6 - 3 = 3x - x
\]
\[
3 = 2x
\]
\[
x = \frac{3}{2} = 1.5
\]
Thus, the value of \( x \) is \( 1.5 \).